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dimaraw [331]
3 years ago
8

Find the equation of the line that has a slope of -2 and passes through the point (5,-3).

Mathematics
1 answer:
andrezito [222]3 years ago
4 0

Answer:

Hi how are you doing today Jasmine

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-2w(w+8) what is the answer
Julli [10]
-2w (w + 8)
 Assuming that it is a polynomial from which you must find the roots, we must first rewrite it:
 -2w (w + 8) = 0
 The roots are then:
 w1 = 0
 w2 = -8
 Assuming you only have to rewrite the expression, the answer is:
 -2w ^ 2 -16w
 Answer:
 w1 = 0 
 w2 = -8
 -2w ^ 2 -16w
5 0
3 years ago
Is theres 10 birds and i shoot 1 how many is there left?
bazaltina [42]
There would be 9 birds left. 10-1=9
3 0
3 years ago
Why are different intervals used when restricting the domains of the sine and cosine functions in the process of defining their
umka21 [38]

Answer:

See below

Step-by-step explanation:

The interval must be chosen so that the function is one-to-one, and the sine and cosine functions are not one-to-one on the same intervals.

3 0
2 years ago
The vertices of the triangle are given. determine whether the triangle is an acute traignel, obtuse triangle
Brrunno [24]
What are the angles?

if all of them are below 90 degrees, it is acute.

if one angle is 90 degress, it is right

if one angle is more than 90 degrees, it is obtuse
8 0
3 years ago
A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
Jet001 [13]
A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
  3 W + 2 M OR (we have found it in c) = 2,520)
  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
  5 W + 0 M OR   ⁸C₅ x ¹⁰C₀   →→→→  =     56

Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
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