The first column contains five pairs of relationships. Determine if each pair forms
1 answer:
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Check the first picture below.
for a parallelogram, it has to have two pairs of parallel sides, so BC || AD and AB || CD.
if two lines are parallel, they have the same slope, namely the <u>same rise and run</u>.
notice, the line BC has a run of 6 and a rise of 1, <u>arrows in red</u>, therefore, AD must also have a run of 6 and a rise of 1, so if we move from A 6 units over and 1 up, we'd end up at point D.
now, for part atop
Check the 2nd picture, in a parallelogram, opposite sides are parallel and opposite angles are equal, so if WLP is 144°, then PNW is also 144°.
in a parallelogram, diagonals bisect each other, so each cut the other in halves, so if PM is 9 then MW is also 9 and thus PW is just 9+9=18.
now, about QRST.
notice what we said about a parallelogram above, thus
so then TQ ==> 2(8) + 12 ==> 16 + 12 ==> 28.
∡Q ==> 8(12) + 13 ==> 96 + 13 ==> 109°.
and since in a parallelogram, adjacent interior angles add up to 180°, then ∡Q + ∡T = 180°.
∡T ==> 180 - 109 ==> 71°.
Answer:
y > -x -3
Step-by-step explanation:
The graph is shaded <em>above</em> the <em>dashed</em> line, indicating y-values in the solution are greater than those on the line, so your inequality will start with ...
y >
The y-intercept of the line is (0, -3), so the "b" value in ...
y > mx +b
will be -3.
The line has a rise of -3 for a run of 3 (between the marked points), so the slope is ...
m = rise/run = -3/3 = -1
Then the inequality you want is ...
y > -x -3
