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oee [108]
2 years ago
11

The first column contains five pairs of relationships. Determine if each pair forms

Mathematics
1 answer:
3241004551 [841]2 years ago
8 0
1. Proportional
2. Not Proportional
3. Not Proportional
4. Proportional
5. Proportional
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L/m/a/o guys i have a 4.00 K/D o the new Call of duty cold war
Softa [21]

Answer:

Step-by-step explanation:

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2 years ago
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Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0
3 years ago
Find the solution to the system of equations. You can use the interactive graph below to find the solution. y=-4x-3 y=-2x+1 x= y
Mama L [17]

Answer:

(-2, 5)

Step-by-step explanation:

I will assume that your system is

y = -4x - 3

y = -2x + 1

Multiplying the second equation by -2 results in

 y = -4x - 3

-2y = 4x - 2

combining these two equations eliminates x temporarily:

-y = -5, so that y must be 5.

Substituting 5 for y in the second equation, we get:

5 = -2x + 1, or

4 = -2x, which results in x = -2

and so the solution is (-2, 5)

4 0
3 years ago
Aaron wants to paints a wall in his office. There are two windows in the wall. The windows have dimensions of 4 feet by 3 feet.
LekaFEV [45]
72 ft
Area of wall- 8•12=96
Area of windows- 2(4•3)=24
96-25=72
8 0
2 years ago
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Assume that all​ grade-point averages are to be standardized on a scale between 0 and 4. How many​ grade-point averages must be
guapka [62]

Answer:

a) The required sample size  n= 55011,57025

b) The sample size is not practical, because that size is extremely large and   would be very costly to collect, normally the size have to be significant but no to large to avoid cost unnecessary

Step-by-step explanation:

Range

σ = \frac{4-0}{4} = 1

E = 0,011 \\c= 99 %\\⇒ 0,99

Sample size can be determinate using equation:

n=(\frac{Z_{\alpha /2 * σ} }{E})^{2}

Using confidence level desired 99% Z_{\alpha /2} = 2,58

Table used :

<em>Confidence         Z_{\alpha/2 }</em>

<em>         90 %                    1,60</em>

<em>         95 %                    1,96</em>

<em>        </em><em> 99 %                    2,58</em>

<em>        99,9 %                  3,291</em>

So replacing:

n=(\frac{2,58 * 1 }{0,011})^{2}

n= 234,5454545^{2} \\n=55011,57025

6 0
3 years ago
Read 2 more answers
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