15% of 20 gal = 0.15 * 20 gal = 3 gal, so the solution contains 3 gal of salt.
If we add <em>x</em> gal of water to the solution, we end up with (20 + <em>x</em>) gal of solution. We want the new mixture to have a concentration of 10%, or
10% of (20 + <em>x</em>) gal = 0.1 * (20 + <em>x</em>) gal = 2 + 0.1<em>x</em> gal
of salt.
The amount of salt in the tank hasn't changed. Solve for <em>x </em>:
2 + 0.1<em>x</em> = 3
0.1<em>x</em> = 1
<em>x</em> = 10 gal
Answer:
-8 + 7
Step-by-step explanation:
7 - 8 = -1
-8 + 7 = -1
Answer:
The volume of the cone is 16.8 in cubed.
Step-by-step explanation:
The formula for a cone is πr^2 multiplied by h/3. The r is radius and h is height. So throwing in the values for the variables we get 16.8 in cubed.
7x^4 +7/x^2 on the interval [-2,3]
