Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
If 40% of students prefer keyboarding, 40/100*40=16 students like it best. If the remaining students prefer English, then 40-16=24 students like English best. Since 24 is more than 16, most students prefer English.
Answer:
30 men
Step-by-step explanation:
In order to be sure that the sample mean does differ from the population mean by more than 0.90, the sample size (n) that should be used is given by:

Where 'Z' , for a 95% probability is 1.960, 's' is the standard deviation of 2.5 inches:

Rounding up to the nearest whole number, the sample size should be at least 30 men.
Answer:
4x^2 + 21x - 18
Step-by-step explanation:
(9x^2+24x-8)-(5x^2+3x+10)
9x^2+24x-8-5x^2-3x-10
9x^2 - 5x^2 = 4x^2
24x - 3x = 21x
-8 - 10 = -18
Answer: 4x^2 + 21x - 18