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saw5 [17]
3 years ago
10

Find the solution to 2/3x = -24

Mathematics
1 answer:
alexira [117]3 years ago
5 0

Answer:

x=-36

Step-by-step explanation:

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Answer:

X and Y = 4

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Find the solution of the system of equations.<br> 3x – 3y = 18<br> 3x – 8y = -2
Oksi-84 [34.3K]

Answer:

x=10, y=4

Step-by-step explanation:

3x-3y=18

(-)3x-(-)8y=-(-)2   -3x+8y=2   add to first equation to eliminate x

5y=20

y=4

substitute y with 4

3x-3(4)=18

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3 years ago
Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 =
Svetradugi [14.3K]

Answer:

\lambda=8,\ \lambda=-5

Step-by-step explanation:

<u>Eigenvalues of a Matrix</u>

Given a matrix A, the eigenvalues of A, called \lambda are scalars who comply with the relation:

det(A-\lambda I)=0

Where I is the identity matrix

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix is given as

A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]

Set up the equation to solve

det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0

Expanding the determinant

det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0

(3-\lambda)(-\lambda)-40=0

Operating Rearranging

\lambda^2-3\lambda-40=0

Factoring

(\lambda-8)(\lambda+5)=0

Solving, we have the eigenvalues

\boxed{\lambda=8,\ \lambda=-5}

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3 years ago
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tiny-mole [99]
Yes it does have a great day
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3 years ago
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