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gogolik [260]
3 years ago
10

Last year, there were 400 students at albright middle school. this year, the student population will increase by 5%. what will b

e the school’s student population this year.
A. 225
B. 20
C. 2000
D. 420
Mathematics
2 answers:
Vadim26 [7]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Stells [14]3 years ago
7 0

Answer:

D.420

Step-by-step explanation:

400 *0.05 = 20 so adding it to 400 will equal to 420

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Answer:

a. ray

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Step-by-step explanation:

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8 0
3 years ago
What is the product of 10.04 and 2.8
natima [27]
The product of two numbers is the result of multiplication.

so 10.04 • 2.8

= 28.112
7 0
4 years ago
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The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 19
alexgriva [62]

Answer:

p(t) = 0.19e0.10t

=>p'(t) = 0.19e0.10t (0.10*1)

=>p'(t) = 0.019e0.10t

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for 2002, t=2002-1994 =8

in 2002

average price =p(8)

=>average price = 0.19e0.10*8

=>average price =0.422853... million

rate of increase =p'(8)

=>rate of increase = 0.019e0.10*8

=>rate of increase =0.0422853... million per year

p(8)=$ 0.42 million

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4 0
3 years ago
If the sum of difference of 13 and 4 divided 64 and 8 is subtracted from the result. Find that number. Mathematical equation plz
natka813 [3]

Answer:

13+4=17,17/64=3-8=-5

Step-by-step explanation:

this is the solution

3 0
3 years ago
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Write the series using summation notation.<br><br> 4 + 8 + 12 + 16 + 20+ . . . + 80
zhannawk [14.2K]

Answer:

\sum ^{20} _{n \to \11} 4n

Step-by-step explanation:

In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;

4, 8, 12, 16, 20...80

The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d

a is the first term = 4

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This shows that the total number of terms in the sequence is 20

According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;

4 + 8 + 12 + 16 + 20+ . . . + 80  = \sum ^{20} _{n \to \11} 4n

4 0
3 years ago
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