Using probability concepts, it is found that:
a) 
probability of drawing a card below a 6.
b) 
odds of drawing a card below a 6.
c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
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- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
Item a:
- In a standard deck, there are 52 cards.
- There are 4 types of cards, each numbered 1 to 13. Thus,
are less than 6.
Then:
probability of drawing a card below a 6.
Item b:
- Converting from probability to odd, it is:
odds of drawing a card below a 6.
Item c:
- The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
- Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
A similar problem is given at brainly.com/question/24233657
Answer:
m=15
Step-by-step explanation:
m/9 + 2/3
x 3 7/3 x 3 = 21/9
m/9 + 6/9 = 21/9
21-6=15
15/9 + 6/9 = 21/9 = 7/3
<span><span>
It introduces the relationship between two variables and is called correlation. Proportionality or variation is state of relationship or correlation between two variables It has two types: </span>direct variation or proportion which states both variables are positively correlation. It is when both the variables increase or decrease together. On the contrary, indirect variation or proportion indicates negative relationship or correlation. Elaborately, the opposite of what happens to direct variation. One increases with the other variables, you got it, decreases. This correlations are important to consider because you can determine and identify how two variables relates with one another. Notice x = y (direct), y=1/x (indirect)</span>
Its 24,000 if the number goes to ten thousand's place..
Answer:
51x^5y^3z^6
Step-by-step explanation:
Please give brainliest
