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Lapatulllka [165]
3 years ago
9

5) How many thousands are there in 2 158 621?​

Mathematics
2 answers:
never [62]3 years ago
6 0

Answer:

2,158,621 = 2 (i think)

Sergio [31]3 years ago
3 0
2




Blah blah blah blah
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4. The distribution of blood cholesterol level in the population of young men aged 20 to 34 years is close to Normal, with mean
Pie

Answer:

a) 38.59% probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

b) By the Central Limit Theorem, the mean of the distribution of the sample mean would be 188 milligrams per deciliter

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 188, \sigma = 41

a. Find the probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

This is 1 subtracted by the pvalue of Z when X = 200. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{200 - 188}{41}

Z = 0.29

Z = 0.29 has a pvalue of 0.6141

1 - 0.6141 = 0.3859

38.59% probability that a young man (aged 20 to 34) has a cholesterol level greater than 200 milligrams per deciliter.

b. Suppose you measure the cholesterol level of 100 young men chosen at random and calculate the sample mean. If you did this many times, i. what would be the mean of the distribution of the sample mean

By the Central Limit Theorem, the mean of the distribution of the sample mean would be 188 milligrams per deciliter

5 0
2 years ago
Determine the length of side c in each of the the triangles below?
Kipish [7]
There are no triangles
5 0
3 years ago
FLVS Question 12 4.10 part two
LUCKY_DIMON [66]
It would be AB because it's going upwards so therefore it's increasing
5 0
3 years ago
Read 2 more answers
The heights of 10000 women students at Eastern College are known to be normally distributed, with a mean of 67 inches and a stan
Lunna [17]
First, convert 5ft 1inch in inches, you will get 61inches, so the probability that you need to find is P(x≤5)
Find z score: Z=(61-67)/3 = -2, with this find the probability from the z table and you get 0.0228= 2.28%, for the answer multiply 10000 by the probability 0.0228*10000= 228 women expected to be shorter that 5ft 1inch (61inches)
3 0
3 years ago
Graph the solution to this inequality on the number line.
patriot [66]

Answer:  Graph is below

=============================================================

Explanation:

We divide both sides by -4 to isolate p. This will flip the inequality sign.

-16 > -4p

-16/(-4) < -4p/(-4)

4 < p

p > 4

The graph has an open hole at 4 and shading to the right. See below.

3 0
2 years ago
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