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harkovskaia [24]
4 years ago
12

The Mercedes S-Class luxury vehicle depreciates by 32.4% after just one year. The starting price in 2015 was $70,000. What is th

e depreciation amount after one year for the Mercedes S-Class vehicle?
Mathematics
1 answer:
nignag [31]4 years ago
4 0
First we need to change the percentage to a decimal so that we are able to use it to solve for the depreciation amount. We do this by dividing by 100:

\frac{32.4}{100}=0.324

Now that we have the decimal form, we can multiply this decimal by the original amount of the vehicle:

0.324*$70,000=$22,680

So now we know that the depreciation amount for this Mercedes is $22,680.
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Marissa and Callie both have babysitting jobs. Marissa charges $19 plus $1.50 per hour. Callie charges $15 plus $2.75 per hour.
aliya0001 [1]

Answer:

4 hours

Step-by-step explanation:

Write an equation

19 +1.5x < 15+2.75x

Subtarct 15 on both sides

4+1.5x<2.75x

subtract 1.5x on both sides

4< 1.25x

Divide 1.25 on each side

3.2<X

Since they on,y charge per hour so 4 hours

3 0
4 years ago
Read 2 more answers
Find the surface area of the figure.<br> 12 in.<br> SA = [ ? ]in.?<br> 5 in.<br> 16 in.
tekilochka [14]

Answer:

SA = 664 in.²

Step-by-step explanation:

Surface area of the rectangular prism = 2(LW + LH + WH)

Where,

Length (L) = 16 in.

Width (W) = 5 in.

Height (H) = 12 in.

Substitute the values

Surface area of the rectangular prism = 2(16*5 + 16*12 + 5*12)

= 2(80 + 192 + 60)

= 2(332)

= 664 in.²

5 0
3 years ago
Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give
frutty [35]

Answer:

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

g(x) =e^{x^3}

  • we know that \frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)

g'(x) =e^{x^{3}}(3 x^{2})

g'(x) =3 x^{2} e^{x^{3}}

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}

using the equation of line:

(y-y_1)=m(x-x_1)

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

3 0
3 years ago
Find the side lengths the cube X
s344n2d4d5 [400]

Answer:

x = 6

Step-by-step explanation:

The volume (V) of the triangular prism is calculated as

V = Al ( A is the area of the triangular end and l is its length )

A = \frac{1}{2} bh = 0.5 × 9 × 4 = 18 cm² , then

V = 18 × 12 = 216 cm³

The volume of a cube is

V = s³ ( s is the side length ) , so

s³ = x³ = 216 ( take the cube root of both sides )

x = \sqrt[3]{216} = 6

7 0
3 years ago
A student factors a^6 - 64 to (a^2-4)(a^4 + 4a^2+ 16).
Neko [114]

Answer:

Option (b) is correct.

The expression is equivalent, but the term is not completely factored.

Step-by-step explanation:

edge 2020

4 0
3 years ago
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