3 years ago

What is the solution to the equation: 3 + 5 = 14 Show work.

Mathematics

1 answer:

butalik [34]3 years ago

4 0

Answer:

You can't solve that I think

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What is the additive inverse of -5a?

vivado [14]

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-5 + 5

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In ℝ2, you are given the points A(−14,15) and X(13,−17). Find t such that the point C(−12,t) lies on the line through A and X. a

Lostsunrise [7]

Answer:

The equation of the line segment between points A and X is

$sA + (1-s)X, s\in[0,1]$

Then we need that the point C satisfy:

$\left[\begin{array}{c}-12\\t\end{array}\right] =\left[\begin{array}{c}-14s\\15s\end{array}\right]+\left[\begin{array}{c}13(1-s)\\-17(1-s)\end{array}\right]$ .

This implies that

$-12=-14s-13s+13\\s=\frac{25}{27}$

We replace the value of s in the equation we get from the second component

$t=15s+17s-17\\t=32\frac{25}{27}-17\\t=\frac{341}{27}$

Then the point $C=(-12,\frac{341}{27})$ lies on the line through A and X.

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