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nikdorinn [45]
3 years ago
10

There are 30 balls numbered 1-30 in a bag. One is randomly selected 12 times. What is the probability of getting a prime number

exactly five times?
Mathematics
1 answer:
Sliva [168]3 years ago
4 0

Answer: The probability of getting a prime number exactly five times = 0.1908

Step-by-step explanation:

Prime numbers from 1 to 30 are 2,3,5,7,11, 13, 17, 19, 23, 29.

The probability of getting a prime number p= \dfrac{10}{30}=\dfrac13

Number of trials n = 12

Binomial probability formula:

P(X=x) = \ ^nC_x p^x(1-p)^{n-x}

, where x= number of successes

n= number of trials.

x = Number of successes

p= probability of getting one success.

The probability of getting a prime number exactly five times:

P(X=5)=\ ^{12}C_5(\frac13)^5(1-\frac13)^{7}

=\frac{12!}{5!7!}(\frac1{243})(\frac{128}{2187})\\\\=0.1908

Hence, the probability of getting a prime number exactly five times = 0.1908

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This questions can be answered with a calculator, but I have an impression it is meant to be a mental calculation problem, which can be solved as follows.

We know that 10*10=100, in otherwords, √ 100 = 10 which is greater than 9.4247.

We also know that √ 108  is greater than √ 100 =10

So we can conclude that
√ 108 > √ 100 = 10  > 9.4247
or simply

√ 108 > 9.4247

by the transitive property of logical propositions.


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