All categories

3 years ago

204, 200,196,... find the 31st term

Mathematics

2 answers:

masya89 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

rewona [7]3 years ago

6 0

Answer:

31st term = 84

Step-by-step explanation:

Given:

204, 200,196,...

Find:

31st term

Computation:

204, 200,196,...

First term a = 204

Difference d = a3 - a2

Difference d = 196 - 200

Difference d = -4

An = a + (n-1)d

A31 = 204 + (31-1)(-4)

A31 = 204 - 120

A31 = 84

You might be interested in

If you add Natalie's age and Fred's age, the result is 36. If you add Fred's age to 4 times Natalie's age, the result is 72.

kozerog [31]

The known facts

the sum of Natalie's age and Fred's age is 36
the sum of Fred's age times four and Natalie's age is 72

Now, let's set up the equations where N is Natalie's age and F is Fred's age.

N + F = 36 ---- equation 1

N + 4F = 72 ---- equation 2

equation 2 minus equation 1 ---> 3F = 36 ---> F = 12, thus N = 24

Thus Fred is 12 years old, and Natalie is 24 years old.

7 0

2 years ago

Read 2 more answers

Steffie makes a scale drawing for a crate with the demensions 15 inches long by 12 inches wide. Her scale factor is 1:3. Brian m

rodikova [14]

Answer:

Dimensions → (5 inches × 4 inches)

Step-by-step explanation:

Scale factor used for the drawing by Steffie = $\frac{1}{3}$

Since, scale factor = $\frac{\text{Dimension of the drawing}}{\text{Actual dimension}}$

For Steffie,

Actual length of the crate = $\frac{\text{Dimension of the drawing}}{\text{Scale factor}}$

= $\frac{15}{\frac{1}{3}}$

= 45 inches

Actual width of the crate = $\frac{12}{\frac{1}{3} }$

= 36 inches

Since Brian used the scale factor = $\frac{1}{9}$

Length of the drawing = Actual length × Scale factor

= 45 × $\frac{1}{9}$

= 5 inches

Width of the drawing = Actual width × Scale factor

= 36 × $\frac{1}{9}$

= 4 inches

Therefore, dimensions of the drawing made by Brian are (5 inches × 4 inches)

6 0

3 years ago

Is 1/5 less than 5/8

iren [92.7K]

1/5 is less then 5/8

3 0

3 years ago

Rewrite (3b) to the second power without the exponents

Alik [6]

3bx3bx3b

27xbxbxb

hope this helps

5 0

3 years ago

If C = 2m2 + m and D = 2 – 6m + 2m², find an expression that equals<br> 2C - 2D in standard form.

lidiya [134]

C = 2m^2 + m
D = 2 - 6m + 2m^2

2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2

2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4

3 0

3 years ago