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tankabanditka [31]

2 years ago

15

Using capital letters and no periods or spaces, type the abbreviation for the congruence postulate.

2 answers:

worty [1.4K]2 years ago

8 0

Answer:

HL

Step-by-step explanation:

jek_recluse [69]2 years ago

6 0

HL is the answer got it from answer key

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From 3 hours to 30 minutes Percentage

omeli [17]

What are u asking ? 30 minutes of 3 hrs the fraction would be 2/6 simplified would be 1/3 and the percentage would be 33.3 repeating percent

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2 years ago

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Craig went bowling with $25 to spend he rented shoes for $5.25 and paid $4dollars for each game what was the greatest number of

BlackZzzverrR [31]

He would play 4 games.

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3 years ago

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Pls help and have a great day <333!!!!

nirvana33 [79]

Answer:

find the least common multiple for the denominator and multiply with the numerator

for the first one,

Step-by-step explanation:

the common multiple for 4 and 6 is 12

4×3=12

6×2=12

multiply the same numbers with the numerator

1×3=3

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8 0

3 years ago

Please help me with this!<br><br><br> show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}

Llana [10]

The set $\{x\mid x^4-x^3-x^2-6x+6=0\}$ is the set of all values of $x$ that are solutions to the given equation. So all you need to do is check whether $x=1$ and $x=2$ satisfy the equation.

$x=1\implies 1^4-1^3-1^2-5+6=0$

$x=2\implies2^4-2^3-2^2-10+6=0$

The equation holds, so both 1 and 2 are solutions, and hence $\{1,2\}$ is a subset of the solutions.

6 0

3 years ago

I need the answer please. Because I think i got mine wrong

Gekata [30.6K]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• $a^{-m}$ ⇔ $\frac{1}{a^{m} }$

• $a^{0}$ = 1

• $a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

(a)

$8^{-2}$ = $\frac{1}{8^{2} }$

(b)

$\frac{1}{3^{-3} }$ = 3³

(c)

$6^{-12}$ × $6^{8}$ × $6^{0}$

= $6^{(-12+8)}$ × 1

= $6^{-4}$

= $\frac{1}{6^{4} }$

7 0

3 years ago

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