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3 years ago

9

A family of 10 purchased tickets to the county fair. Tickets for adults cost $6 and tickets for children cost $3. If the total c

ost of the tickets was $42, how many family members were adults and children?

2 answers:

blsea [12.9K]3 years ago

4 0

Answer:

3 adults 2 children

Step-by-step explanation:

(3 x 10) + (2 x 6)

30+12=42

Eva8 [605]3 years ago

4 0

Answer:

Step-by-step explanation:

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Answer:

5,5 -5,5

Step-by-step explanation:

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3 years ago

How do I simplify before multiplying

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6x2 = 12

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3 years ago

A camera regularly priced at 295 was placed on sale at 236. What percent of the regular price was the sale price?

skad [1K]

Answer:

80%

Step-by-step explanation:

regular price was given as $295.

The sale of the camera was $236.

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3 years ago

Substitute<br>x+y =200<br>9.5x+27y=4000

Vera_Pavlovna [14]

Point form: (80,120)
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3 years ago

According to The Wedding Report, Inc., the mean cost for a wedding in the United States is $28732 (as of November 2008). Suppose

Stella [2.4K]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

$X = \text{cost of wedding}\sim \text{Normal}\ (\mu = 28732, \sigma= 1500)\\\\$

For point a:

$Probability\ = 0.00000359\\\\ \text{(Using Excel function:} =NORMDIST(22000,28732,1500,1)).$

For point b:

$Probability \ = 0.014678\\\\\text{(Using Excel function:} =1-NORMDIST(32000,28732,1500,1))\\\\$

For point c:

$Probability\ = 0.794614436 \\\\$

$\text{(Using Excel function:} \\=NORMDIST (30000,28732,1500,1)-NORMDIST(25000,28732,1500,1))\\\\$

For point d:

$Q_1 = 27720.26537 \\\\\text{(Using Excel function:} =NORMINV(0.25,28732,1500)) \\\\Q_3 = 29743.73463 \\\\\text{(Using Excel function:} =NORMINV(0.75,28732,1500)).$

For point e:

$IQR = Q_3 - Q_1 = 29743.73463 - 27720.26537 = 2023.469251.$

For point f:

$Top\ 10\% = 30654.32735 \\\\\text{(Using Excel function:} =NORMINV(0.9,28732,1500)).$

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3 years ago