Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
Answer:
The second one decreasing on the interval (-infinity, 0) where it becomes constant
Answer:
C. Quadrant I
Step-by-step explanation:
For a fact, that with radioactive substance it will decay and never stop halving itself. So the line of amount of radioactive substance always halves in a specific time. This type of graph are done in a positive unit grids, never on a negative because that would mean, the radioactive substance rather decaying, its absorbing. So the answer will be Quadrant I.
Visual likewise graph given below.
Answer:
-2
Step-by-step explanation:
M = (y - yo/x - xo)
(-6 + 2) / (0 + 2)
-4 / -2
= - 2