Answer:
16.67% of your day is spent in math class.
Step-by-step explanation:
The total would be 100% and then since you have 6 periods we divide 100 by 6 to get 16.67%. So 16.67% of your day is spent in math class.
Answer:
7
Step-by-step explanation:
edge
Answer:
Step-by-step explanation:
f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4
Step 1. Calculate the difference between the functions
(a) Write the two functions, one above the other, in decreasing order of exponents.
ƒ(x) = 9x³ + 2x² - 5x + 4
g(x) = 5x³ - 7x + 4
(b) Create a subtraction problem using the two functions
ƒ(x) = 9x³ + 2x² - 5x + 4
-g(x) = <u>-(5x³ - 7x + 4)
</u>
ƒ(x) -g(x)=
(c). Subtract terms with the same exponent of x
ƒ(x) = 9x³ + 2x² - 5x + 4
-g(x) = <u>-(5x³ - 7x + 4)
</u>
ƒ(x) -g(x) = 4x³ + 2x² + 2x
Step 2. Factor the expression
y = 4x³ + 2x² + 2x
Factor 2x from each term
y = 2x(2x² + x + 1)
Since every figure repr. an equil. triangle, each of the angles shown is 60 deg.
Thus, the height of one of the shaded triangles is s sin 60 deg, or s/sqrt(3).
The base of one such triangle is s/3.
Thus, the area of ONE shaded triangle is A = bh/2, which here is
(s/3)(s/sqrt(3) ) (s/3)(s)
A = ----------------------- = --------------------
2 2sqrt(3)
Rationalize the denom.: Mult numerator and denominator both by sqrt(3), and then mult the resulting numerator and den by 3:
sqrt(3) s^2/3 s^2*sqrt(3) s^2*sqrt(3)
----------- * ----------- = ----------------- = ----------------
sqrt(3) 2sqrt(3) 3*2*3 18
Unfortunately, this does not agree with any of the four answer choices.
Let's take a slightly different approach here:
Each (horizontal) base of each shaded triangle has length s/3. Each has height (s/3)sin(60 deg) = s*sqrt(3)/(3*2) = s*sqrt(3)/6.
[s/3]*[s*sqrt(3)]/6
Then each shaded triangle has area A = bh/2 = ----------------------------
2
and the total shaded area is three times that:
s^2 * sqrt(3) s^2*sqrt(3)
Total area = -------------------- = ------------------ (answer)
3*2 * 6 36
Answer:
10
Step-by-step explanation:
