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Ghella [55]
3 years ago
15

You are part of a school and have to report the results of standardized test scores. Which measure of central tendency would you

use? Assume that you don't know how your students will perform; consider the general effects of outliers on the three measures of central tendency. Research and summarize the general effects that outliers have on each of the measures of central tendency. Then, using some real values, provide an example of how the three measures of central tendency vary due to outlier effects.
Mathematics
1 answer:
ohaa [14]3 years ago
8 0
Escucha no me gustaria escucha
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Which is the solution set of the compound inequality 3.5 x minus 10 greater-than negative 3 and 8 x minus 9 less-than 39
dexar [7]

The solution for the compound inequality is x \in(2,6)

Explanation:

The equations are 3.5x-10>-3 and 8x-9

To find the solution set for these compound inequalities, we need to solve the inequality.

First, we shall solve the inequality 3.5x-10>-3

Adding both sides of the equation by 10, we have,

3.5x>7

Dividing both sides by 3.5, we get,

x>2

Now, we shall solve the inequality 8x-9,

Adding both sides of the equation by 9, we have,

8x

Dividing both sides by 8, we get,

x

Thus, the solution set for the inequalities 3.5x-10>-3 and 8x-9 is x \in(2,6)

4 0
3 years ago
Read 2 more answers
Select the correct answer.<br> Simplify the expression.
gregori [183]

Answer:

Option D :- \sf \: 18 {x}^{2}  {y}^{2}     \sqrt[3]{3 {xy}^{2} }

Step-by-step explanation:

\sf \: 3x\sqrt[3]{648  {x}^{4}  {y}^{8} }

transform the equation

\rightarrow \sf \: 3x\sqrt[3]{ {6}^{3}  \times  {3x}^{2}   \times   {xy}^{6}  \times  {y}^{2} }

rewrite the expression

\rightarrow \sf \: 3x  \times \sqrt[3]{ {6}^{3}}  \times\sqrt[3]{  {3x}^{2}}   \times \sqrt[3]{ {xy}^{6} } \times \sqrt[3]{{y}^{2} }

Simplify the radical expression

\rightarrow \sf \: 3x  \times  {6xy}^{2} \sqrt[3]{3xy {}^{2} }

Multiply

\sf \: 18 {x}^{2}  {y}^{2}     \sqrt[3]{3 {xy}^{2} }

8 0
2 years ago
turin the numbers 5x-4 6x-23 -2x+33 into a expression and them simplify the expression. PLZ HELP ME!!!!!!!!!!!!!!!!!!!!!! ITS WO
lapo4ka [179]

Answer:

This expression is missing operators and has no meaning. If you add commas to separate the expressions, and equals signs where appropriate, then assistance can be given.

Assuming that the blank spaces between terms are meant to be plus signs, then the final answer would be 9x.

Step-by-step explanation:

To make some sense of this, let's assume that the operator between "5x-4" and "6x-23" is a plus sign, and that the minus sign on "-2x + 33" is itself the operator there.  If that is the case then this can be solved by simply grouping like terms and summing them up:

5x - 4 + 6x - 23 - 2x + 33

group like terms:

5x + 6x - 2x - 4 - 23 + 33

(5 + 6 - 2)x + (-4 - 29 + 33)

The numbers with no coefficient add up to zero:

9x + (0)

Leaving us with the final answer.

9x

3 0
3 years ago
If ab ac cb in abc then which of the following is true
JulijaS [17]

Answer:

The answer is c. Sorry my last answer was wrong i think. If its abc its probably the other way around i didnt see which way it was going. Though if i was right the first time its either a or c

Step-by-step explanation:

4 0
3 years ago
A bee flies at 15 ft./s directly into a flower bed from a time the beast stays at the flower bed for 12 minutes and then flies d
Zinaida [17]

A) The equation that we need to solve is:

(12ft/s)*(- d/(15ft/s) + 300s) = d

B) The distance to the hive is d = 2000ft.

<h3 /><h3>What equation can you use to find the distance of the flower bed from the hive?</h3>

We know that the bee's speed is 15 ft/s from the hive to the flower bed.

Then stays 12 minutes at the flower bed.

Then returns to the hive with a speed of 12ft/s.

The total time of the journey is 17 minutes, discounting the 12 minutes that the bee was in the flower bed, the travel only took 5 minutes.

Now, if the distance between the hive and the flower bed is d, t₁ as the time that the bee needs to go from the hive to the flower bed, and t₂ as the time in which the bee goes from the flower bed to the hive, we can write the system of equations:

t₂ + t₁ = 5min

(15ft/s)*t₁ = d

(12ft/s)*t₂ = d

With that system of equations, we can find the value of d, which is what we want to get.

Isolating t₂ in the first equation we get:

t₂ = - t₁ + 5min

Now we can replace that in the third equation:

(15ft/s)*t₁ = d

(12ft/s)*(- t₁ + 5min) = d

In the first equation we can isolate t₁:

t₁ = d/(15ft/s)

And replace that in the remaining equation:

(12ft/s)*(- d/(15ft/s) + 5min) = d

5 min = 5*60s = 300s

(12ft/s)*(- d/(15ft/s) + 300s) = d

This is the equation we need to solve to find the value of d.

-(12/15)*d + 3600ft = d

3600ft = d + (12/15)*d = (1 + 12/15)*d = (27/15)*d

(15/27)*3600ft = d = 2000 ft

We conclude that the distance to the hive is 2000ft.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

8 0
2 years ago
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