8/20 of a minute or 2/5 of a minute
Since a product in maths means the result after multiplying numbers, you need to multiply 2 prime numbers and get 4.
If we look at the prime numbers: 2, 3, 5, 7, 11, etc, we see that the only number we can multiply to get 4 is 2, or, in other words, the only multiplication of prime numbers we can do to get four is 2*2=4.
Answer:
![\sqrt[3]{ - 0.125} = \sqrt{ - 1} \times \sqrt[3]{0.125 } \\ = 5i](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20-%200.125%7D%20%20%3D%20%20%5Csqrt%7B%20-%201%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B0.125%20%7D%20%20%5C%5C%20%20%3D%205i)
here i equals √-1
Step-by-step explanation:
Answer is 5i
If you have any doubts write in comments box.
HAVE A NICE DAY !
Isolate the variable by dividing each side by factors that don't contain the variable.
f=e-g/d
We can model this situation with an arithmetic series.
we have to find the number of all the seats, so we need to sum up the number of seats in all of the 22 rows.
1st row: 23
2nd row: 27
3rd row: 31
Notice how we are adding 4 each time.
So we have an arithmetic series with a first term of 23 and a common difference of 4.
We need to find the total number of seats. To do this, we use the formula for the sum of an arithmetic series (first n terms):
Sₙ = (n/2)(t₁ + tₙ)
where n is the term numbers, t₁ is the first term, tₙ is the nth term
We want to sum up to 22 terms, so we need to find the 22nd term
Formula for general term of an arithmetic sequence:
tₙ = t₁ + (n-1)d,
where t1 is the first term, n is the term number, d is the common difference. Since first term is 23 and common difference is 4, the general term for this situation is
tₙ = 23 + (n-1)(4)
The 22nd term, which is the 22nd row, is
t₂₂ = 23 + (22-1)(4) = 107
There are 107 seats in the 22nd row.
So we use the sum formula to find the total number of seats:
S₂₂ = (22/2)(23 + 107) = 1430 seats
Total of 1430 seats.
If all the seats are taken, then the total sale profit is
1430 * $29.99 = $42885.70
