All categories

2 years ago

Please look a the pic also you need to find the area

Mathematics

2 answers:

zloy xaker [14]2 years ago

6 0

Do u still need help

iogann1982 [59]2 years ago

4 0

Answer:

area of circle is 113.04 (i used 3.14 for pi) 3.14 x 6^2

area of square is 24 - 12 x 2 = 24

area of square without circle is 89.04 - 113.04 - 24 = 89.04

Step-by-step explanation:

You might be interested in

If Hector is 8 years old and Mary is 3 years old how old will Mary be when Hector is 16

IRINA_888 [86]

Okay so 8 (hector) - 3(Mary) = 5 years apart
So, 16 (hector) - 5 (years apart) = 11 (Mary’s age)

7 0

3 years ago

How do i add and subtract polynomials?<br>(4v-6v)-(v-5v^3)+(5v^3+4)

Ksenya-84 [330]

Distribute and add like terms and you are good

alirghty

we can make it easier by simplifying what we can

(4v-6v)=-2v so

(-2v)-1(v-5v³)+(5v³+3)=
-2v-v+5v³+5v³+3=
10v³-3v+3

7 0

3 years ago

What is the slope of the line on the graph?

Lelechka [254]

Answer:

5,-1,-7

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

CaHeK987 [17]

Answer:

1 and 4, 2 and 3, 5 and 8, 6 and 7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers