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kakasveta [241]
3 years ago
12

HELP PLS SHOW WORK ITS 2 PARTS

Mathematics
2 answers:
sdas [7]3 years ago
7 0

Answer:

a=4.2

Step-by-step explanation:

6.4-a=2.2

so 6.4-22=a

4.2=a

jok3333 [9.3K]3 years ago
6 0

Answer:

C

Step-by-step explanation:

6.4 - 2.2 = 4.2

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The sum of reciprocals of rehman’s ages 3 years ago and 5 years from now is 1/3. Find his present age
Afina-wow [57]

Answer:

His age is 7 years.

Step-by-step explanation:

Let Rehman's  present age be x years.

1 / (x - 3) + 1 /(x + 5) = 1/3

Multiply through by the LCD 3(x - 3)(x + 5):

3(x + 5) + 3(x - 3) = (x + 5)(x - 3)

3x + 15 + 3x - 9 = x^2 + 2x - 15

x^2 + 2x - 6x - 30 + 9 = 0

x^2 - 4x - 21 = 0

(x - 7)(x + 3) = 0

x = 7  (answer).

6 0
3 years ago
The height of a 12-year-old boy increased by 17% last year and by 12% this year. What is the total increase in percentage terms?
murzikaleks [220]

Answer:

1. 12(1.17h) = 1.3104h Which is a 31.04% increase

Step-by-step explanation:


6 0
3 years ago
How much money was taken off the 1000RM loan for every child born to
grigory [225]

Answer:

2

Step-by-step explanation:i have no clue

4 0
3 years ago
Factor 80t - 16t = 0<br><br> help?
Alinara [238K]
I don't know if that is factor-able. It looks like you could just subtract and get 64t. which would lead to the answer being zero since you divide by zero when isolating the variable t.
6 0
3 years ago
Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m
laila [671]
Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of t_{ \frac{1}{2} } after t years is given by

N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\  \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\  \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\  \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
5 0
3 years ago
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