What is anequation of the line that passes through the points (-3, 8) and (-7,8)?
1 answer:
The equation of a line is given by the expression:
y=Mx + b
This is the slope form of an equation where M is the gradient of line and b is the y intercept.
For the slope, M= change in y values/ change is x values
(-3,8) , (-7,8) thus the slope m,=(8-8)/(-7--3)
m=0/-4 =0
the slope is 0
To find the b substitute the values in the equation y=Mx+b
Taking point (-3,8) and slope of 0
y=Mx+b
8=0*(-3) + b
8=0+b
8=b
The value of b is 8
The equation of the line will be;
The equation of the line is y=8
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Answer:
3x +8y = -17
Step-by-step explanation:
The point-slope equation is a good place to start.
y -k = m(x -h) . . . . . equation through (h, k) with slope m
Filling in your numbers gives ...
y +4 = -3/8(x -5)
Multiplying by 8, we get
8y + 32 = -3x + 15
Adding 3x-32 puts this in standard form.
3x + 8y = -17
_____
Standard form is ...
ax +by = c
where a, b, c are mutually-prime integers and the leading coefficient is positive. (If a=0, the leading coefficient is b.)
