Question

What is anequation of the line that passes through the points (-3, 8) and (-7,8)?

Answer 1

The equation of a line is given by the expression:

y=Mx + b

This is the slope form of an equation where M is the gradient of line and b is the y intercept.

For the slope, M= change in y values/ change is x values

(-3,8) , (-7,8) thus the slope m,=(8-8)/(-7--3)

m=0/-4 =0

the slope is 0

To find the b substitute the values in the equation y=Mx+b

Taking point (-3,8) and slope of 0

y=Mx+b

8=0*(-3) + b

8=0+b

8=b

The value of b is 8

The equation of the line will be;

$y-8=0(x+3)$$y-8=0$$y=8$

The equation of the line is y=8