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1 year ago

What is anequation of the line that passes through the points (-3, 8) and (-7,8)?

Mathematics

1 answer:

zaharov [31]1 year ago

7 0

The equation of a line is given by the expression:

y=Mx + b

This is the slope form of an equation where M is the gradient of line and b is the y intercept.

For the slope, M= change in y values/ change is x values

(-3,8) , (-7,8) thus the slope m,=(8-8)/(-7--3)

m=0/-4 =0

the slope is 0

To find the b substitute the values in the equation y=Mx+b

Taking point (-3,8) and slope of 0

y=Mx+b

8=0*(-3) + b

8=0+b

8=b

The value of b is 8

The equation of the line will be;

$y-8=0(x+3)$ $y-8=0$ $y=8$

The equation of the line is y=8

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Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

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False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

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The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)

⇒ P(-/H) = P(- ∩ H)

P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= P(+ ∩ S)

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The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) = P(+ ∩ S)

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P(+/S)* P(S) = P(+ ∩ S)

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P(+)= P(+ ∩ S) + P(+ ∩ H)

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Then you can clear the value of P(+ ∩ H):

P(+/H) = P(+ ∩ H)

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P(+/H)*P(H) = P(+ ∩ H)

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Next you can calculate P(+):

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Now you can calculate the asked probability:

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I hope it helps!

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