What is anequation of the line that passes through the points (-3, 8) and (-7,8)?
1 answer:
The equation of a line is given by the expression:
y=Mx + b
This is the slope form of an equation where M is the gradient of line and b is the y intercept.
For the slope, M= change in y values/ change is x values
(-3,8) , (-7,8) thus the slope m,=(8-8)/(-7--3)
m=0/-4 =0
the slope is 0
To find the b substitute the values in the equation y=Mx+b
Taking point (-3,8) and slope of 0
y=Mx+b
8=0*(-3) + b
8=0+b
8=b
The value of b is 8
The equation of the line will be;
The equation of the line is y=8
You might be interested in
The given inequality is:
This inequality can be divided in two parts as:
a)
b)
Solving part a:
Solving part b:
Therefore, the solution to the given inequality is
and 
. Combining both the ranges we get the solution: 
.
In interval notation, this solution can be expressed as [1,5]
This inequality can be divided in two parts as:
a)
b)
Solving part a:
Solving part b:
Therefore, the solution to the given inequality is
In interval notation, this solution can be expressed as [1,5]