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3 years ago

The time period, T, of a simple pendulum is directly proportional to the square root of the length, d, of the pendulum.

Mathematics

1 answer:

bearhunter [10]3 years ago

4 0

Answer: T= 3.54

Step-by-step explanation:

Step 1

Given that

The time period, T, s doirectly proportional to the square root of the length, d, of the pendulum, we have that

T ∝ $\sqrt{d}$

Introducing the constant of proportionality, we have that

T= K $\sqrt{d}$ .

Step 2

When d=6, T=5, K =?

T= K $\sqrt{d}$ .

5 = k $\sqrt{6}$

5= k x 2.44949

k =5/2.44949

k =2.041

Therefore, when d = 3 , T= ?

T= K $\sqrt{d}$

T= 2.041 x $\sqrt{3}$

T= 3.53511≈ 3.54

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