The efforts applied are 320Nm.
What is work or effort?
Work is when we apply force on body and displacement occur are called work .
W= Fs
where F is force and s is displacement .
displacement is 2-1.6
. = 0.4m
By applying the value in formula
We have given F =800N
W= 800× 0.4
W= 320Nm.
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Answer:
D
Explanation:
What can be infer from Mr. F situation is that his body is raising blood pressure by both increasing blood volume with all this fluid intake and increasing heart rate. Something may be wrong with his blood volume.
Answer:
The length of the object in kilometer (km) is 70 x 10⁻⁹ km
The width of the object in kilometers (km) is 47.66 x 10⁻⁹ km
Explanation:
Given;
length of the object = 70 micrometer = 70 μm
the width of the object = 47.66 micrometer = 47.66 μm
The length of the object in meter:
70 micrometer = 70 μm = 70 x 10⁻⁶ m
The length of the object in kilometer (km):
70 x 10⁻⁶ m = 70 x 10⁻⁹ km
The width of the object in meters:
47.66 micrometer = 47.66 μm = 47.66 x 10⁻⁶ m
The width of the object in kilometers (km):
47.66 x 10⁻⁶ m = 47.66 x 10⁻⁹ km
Answer:
Explanation:
a) Power consumption is 4100 J/min / 60 s/min = 68.3 W(atts)
work done raised the potential energy
b) 75(9.8)(1000) / (3(3600)) = 68.055555... 68.1 W
c) efficiency is 68.1 / 68.3 = 0.99593... or nearly 100%
Not a very likely scenario.
In most cases the temperature must increase for thermal expansion to occur. Most substances expand as temperature increases because the atoms or molecules vibrate faster as temperature increases and experience greater separation.