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2 years ago

What is the de broglie wavelength of a 149-g baseball traveling at 95.4 mph? (1 mile = 1.609 km, h = 6.63 × 10–34 j·s)?

Physics

1 answer:

boyakko [2]2 years ago

5 0

The solution for the problem is:

Wavelength = Planck’s constant/(mass*velocity)

Planck’s constant= 6.63*10^-34 with units of J-s or kg-m^2/s^2-s

mass = 149g = 0.149 kg

velocity = 95.4.mi/1hr(1609.3m/1mi)(1hr/3600sec) = 42.65m/s

h/mv = 6.63*10^-34 kg-m^2/s^2-s/(42.65m/s*0.149kg)

wavelength = 1.04 *10^-34 m

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The distance between two slits is 1.50 *10-5 m. A beam of coherent light of wavelength 600 nm illuminates these slits, and the d

Fed [463]

Answer: y = 2.4×10^-6m or y= 2.4μm

Explanation: The formulae for the distance between the central bright fringe to any other fringe in pattern is given as

y = R×mλ/d

Where y = distance between nth fringe and Central bright spot fringe.

m = position of fringe = 4

λ = wavelength of light= 600nm = 600×10^-9 m

d = distance between slits = 1.50×10^-5m

R = distance between slit and screen = 2m

y = 2 × 4 × 600×10^-9/2

y = 4800×10^-9/2

y = 2400 × 10^-9

y = 2.4×10^-6m or y= 2.4μm

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3 years ago

The chart shows data for a moving object.

Ipatiy [6.2K]

Answer:

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Explanation:

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3 years ago

A beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3

PtichkaEL [24]

Answer:2.47

Explanation:

So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!

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2 years ago

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lord [1]

I would say the plastic grip because glass, wood, and plastic are all good conductors of electricity

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3 years ago

A certain superconducting magnet in the form of a solenoid of length 0.300 m can generate a magnetic field of 8.90 T in its core

Ivan

Answer:

The number of turns in the solenoid is 22366.

Explanation:

The number of turns in the solenoid can be found using the following equation:

$B = \mu_{0} I\frac{N}{L}$

Where:

B: is the magnetic field = 8.90 T

L: is the solenoid's length = 0.300 m

N: is the number of turns =?

I: is the current = 95 A

μ₀: is the magnetic constant = 4π×10⁻⁷ H/m

By solving equation (1) for N we have:

$N = \frac{BL}{\mu_{0} I} = \frac{8.90 T*0.300 m}{4\pi \cdot 10^{-7} H/m*95 A} = 22366 turns$

Therefore, the number of turns in the solenoid is 22366.

I hope it helps you!

8 0

3 years ago