10.2 hours is equivalent to three half-lives, so after 10.2 hours, the mass of the sample would have decayed by half three times over. If one starts with 100 mg of the sample, then after three half-lives, there would be 100(0.5)³ = 12.5 mg of the sample remaining.
Thus, the correct answer choice here would be D.
Is this comprehensive writing?
I must say if it is, it's great writing!
If not, is this your experience?
{And if it is, am so sorry. I can't say I understand what you're passing through but know that you and your siblings plus your mom are worth it. All the male parent figures that were supposed to be there and fufill their duties and didn't just know that what awaits them is God's payment. Trusting in God's Way will never let us down. Though life might look bleary and you said so that you don't know the future but that's the beauty of life only God knows. Therefore, pray without ceasing and trust in God and remember there are a lot of things to be thankful for your life, your mom, your siblings, your education, your bf.
(God is always saying something)
Much love to you. I pray everything gets better for you. The best is always yet to come.}
All the best! :)
Answer:
http://www.clearwater.org/news/dredge.html
There are C(29, 4) = 29!/(4! (29 - 4)!) ways of selecting any 4 students from the total 21 + 8 = 29 students.
The teacher has C(21, 2) = 21!/(2! (21 - 2)!) ways of picking out 2 sophomores and C(8, 2) = 8!/(2! (8 - 2)!) ways of picking out 2 freshmen, so there are
C(21, 2) • C(8, 2) = 5880
possible ways of picking out 2 sophomore and 2 freshmen.
The probability of picking out a group of students like this is then
C(21, 2) • C(8, 2) / C(29, 4) = 280/1131 ≈ 0.2476
Answer:
I'm so sorry, but where are the links and what is (are) the question (s)?
Explanation:
