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aksik [14]
3 years ago
9

Please help this is confusing:(

Mathematics
1 answer:
topjm [15]3 years ago
6 0
The answer would be 17
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Kerry ordered a pizza: one half was topped with
myrzilka [38]

Answer:

3/10

Step-by-step explanation:

If both halves were equal.

½ × ½ = ¼

Closest option is 3/10

4 0
3 years ago
Solve the problem below
wlad13 [49]

Answer:

(5,0)

Step-by-step explanation:

an x-intercept is where the line crosses the x-axis. in this case it crosses it multiple time so other possible answers could be (1,0) or (-1,0)

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3 years ago
Help<br><br><br><br><br><br> 4/10 as a decimal
Rom4ik [11]
0.4 is 4/10 in decimal form.
6 0
1 year ago
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Work out the area of a parallelogram of base 6cm and height 8cm
trapecia [35]
The formula to find the area of a parallelogram is: A=bh (b standing for your base, and h for height) You substitute 6 and 8 into your formula and your answer is 48cm^{2}
7 0
3 years ago
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Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

5 0
3 years ago
Read 2 more answers
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