This is how the sketch should look on your graph!
Answer:
B i think
Step-by-step explanation:
sorry I'm not explaining I'm doing a challange
Answer: 
Step-by-step explanation:
Slope of a line passes through (a,b) and (c,d) = 
In graph(below) given line is passing through (-2,-4) and (2,2) .
Slope of the given line passing through (-2,-4) and (2,2) =
Since parallel lines have equal slope . That means slope of the required line would be .
Equation of a line passing through (a,b) and has slope m is given by :_
(y-b)=m(x-a)
Then, Equation of a line passing through(-3, 1) and has slope = is given by

Required equation: 
I mean, this isn't a question but its true?
Answer:
Either one of these.
Step-by-step explanation:
volumepile=1/3 (PI r^2)h
but r=h/2, so
volume=1/12 PI h^3
dv/dt=10 ft^3/min
but dv/dt=1/12 PI 3h^2 dh/dt
solve for dh/dt
This assumes you mean by "altitude" the height. If you mean altitude as slant height, you have to adjust the fromula
_______________________________________________
given: r = h/2
V = (1/3)π r^2 h
= (1/3)π (h/2)^2 (h)
= (1/12) π h^3
dV/dt = (1/4)π h^2 dh/dt
for the given data ...
10 = (1/4)π(25)dh/dt
dh/dt = 10(4)/((25π) = 1.6/π feet/min