Multiply x(x^2+2x+4) and -2(x^2+2x+4) Combine like terms: Final answer:

Which equation shows the value of -2/5 - -9/15

Alika [10]

Answer:

D) 3/15

Step-by-step explanation:

(-2/5) - (-9/15) = (-6/15) - (-9/15) = (-6/15) + (9/15) = 3/15

6 0

3 years ago

With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t

Klio2033 [76]

Answer:

Part a) $a=4g+10$ (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

The complete question is

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

$a=mg+b$

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

$m=\$4\ per\ game$

$b=\$10$

substitute

$a=4g+10$

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> $a=4(0)+10=\$10$

For g=1 ----> $a=4(1)+10=\$14$

For g=2 ----> $a=4(2)+10=\$18$

For g=3 ----> $a=4(3)+10=\$22$

For g=4 ----> $a=4(4)+10=\$26$

The table is

$\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]$

Part c) Use the values from your table to draw a graph

we have the ordered pairs

$(0,10),(1,14),(2,18),(3,22),(4,26)$

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

6 0

3 years ago

2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c A= B= C= Please I'm gonna fail math

aleksley [76]

9514 1404 393

Answer:

a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

(a^b)^c = a^(bc)

___

You seem to have ...

$\dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)$

_____

Additional comment

I find it easy to remember the rules of exponents by remembering that an exponent signifies repeated multiplication. It tells you how many times the base is a factor in the product.

$2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}$

Multiplication increases the number of times the base is a factor.

$(2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5$

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

$\dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1$

5 0

3 years ago

What is the solution to the equation? 1/7g=3/14

Crazy boy [7]

Answer:

g = 21/4

Decimal form:

g = 5.25

Mixed Number:

5 1/4

6 0

3 years ago

When do you hear/use imperial measures in Canada?

castortr0y [4]

Answer:

Canadians typically use a mix of metric and imperial measurements in their daily lives. Although Canadian driver's licences give height in centimetres, many Canadians also use imperial units to indicate height and weight.

5 0

3 years ago