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3 years ago

Two angles are complementray, one angle is 10 degree greater then the angle. how many degrees are in each angle.

1 answer:

7 0

Complementary means they add up to 90.

Split 90 in half. 45,45
Decrease one half by 5, and increase the other by 5
40,50
The angles are 40 and 50 degrees

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Find the solution of given expression !!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B36%20%5Ctimes%204%7D%20" id="TexF

Law Incorporation [45]

$\huge{ \mathfrak{ \underline{ Answer }\: \: ✓ }}$

Let's Solve :

$\sqrt{36 \times 4}$

$\sqrt{2 \times 2 \times 3 \times 3 \times 2 \times 2}$

$2 \times 3 \times 2$

$12$

Therefore, the correct answer is 12

_____________________________

$\mathrm{ ☠ \: TeeNForeveR \:☠ }$

6 0

3 years ago

John, Sally, and Natalie would all like to save some money. John decides that it

brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

Help me factor this completely

Tanya [424]

-12z^4 (x y^2 z^3 + 1)

7 0

3 years ago

During the regular season, a National Basketball Association team plays 82 games and a National Football League team plays 16 ga

Naddika [18.5K]

Answer:

NFL teams play 16 regular season games each year, NHL and NBA teams play 82, while MLB teams play 162-could invalidate direct comparisons of win percentages alone. As an example, the highest annual team winning percentage is roughly 87% in the NFL but only 61% in MLB and part (but not all) of that difference is undoubtedly tied to the shorter NFL regular season

5 0

3 years ago

Maggie had 20 ribbons. 2/5 of the ribbons are polka-dot Ted ribbons. how many are not polka-dotted?

Solnce55 [7]

12 ribbons
p.s: im in 7th grade so you can trust me

5 0

3 years ago

Read 2 more answers