If your answer was d) 3.6 , then you are correct!
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
G(-3)= 3(-3)+4
g(-3) = -5
Answer:
The scale factor would be 1/2.
Step-by-step explanation:
2 of the sides both are 4 units.
If you go to figure B, it got smaller.
So in this case, you would divide.
On figure B, 2 of the sides are 2 units.
If you did it in reverse, you would get 2 because 2 times 2 is 4.
But we divide, so 4/2 is 2, so the scale factor would be:
1/2
Hope this helped!
And brainliest pls :)
Answer:
C
Step-by-step explanation:
add them
