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sweet-ann [11.9K]
3 years ago
12

Please help!! It’s engenuity.

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

9514 1404 393

Answer:

  (c)  1/(36·a^4·b^10)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

  a^-1 = 1/a

__

  \left(\dfrac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}\right)^{-1}=\dfrac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}=\dfrac{3^{-2}a^{-10}b^{-2}}{2^2a^{-6}b^8}=\dfrac{1}{3^22^2}a^{-10-(-6)}b^{-2-8}\\\\=\boxed{\dfrac{1}{36a^4b^{10}}}

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What is the 70th term of the sequence 5, 7, 9, 11
photoshop1234 [79]

Answer:

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3 0
3 years ago
(- 6) × (- 6) × (- 6) × (- 6) =
andrey2020 [161]
-6*-6*-6*-6 = 1,296

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7 0
3 years ago
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<span>Please, post only one question at a time.

The line passing through (1,4) and (-4,-1) has the following slope:

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3 years ago
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4 0
3 years ago
If tv =74 and wv = 4x + 1, solve for x
barxatty [35]

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Step-by-step explanation: The figure in the question is a Rhombus and one of the properties of a rhombus states that “the diagonals bisect each other.”

This means line SU bisects line TV into two equal parts at point W. This also means that line WV is half of line TV. If line TV equals 74 and line WV equals 4x + 1, then we have the following;

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8 0
4 years ago
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