You have to distribute the 7 to x and 2 so :
7x+14=2x-1
Add one to both sides (inverse operations)
7x+14=2x-1
+1 +1
7x+15=2x
Cross Cancel by subtracting 7x from both sides
7x+15=2x
-7x -7x
15=-5x
Divide by -5
15/-5= -5/-5
X= -3
Answer:
-75
Step-by-step explanation:
Let us consider the first odd number to be 'x'.
Thus:
- 1st odd number: x
- 2nd odd number: x+2
- 3rd odd number: x+3
According to the question, the sum of these three consecutive ODD numbers should be equal to -219
So,
x + x + 2 + x + 4 = -219
3x + 6 = -219
3x = -225
x = -75
Answer:
B
Step-by-step explanation:
Also solved eveything
(x+9)^2=49
x^2+18x+81=49
x^2+18x+32=0
a=1, b=18 and c=32
x= (-18 +/- Sqrt (18^2-4×32))/2
x= (-18 +/- Sqrt (324-128))/2
x= (-18 +/- Sqrt (196))/2
x= (-18 +/- 14)/2
x= (-18 +14)/2 = -4/2 =-2
OR
x= (-18 -14)/2 = -32/2 =-16
Answer:
D. 11.8 cm
Step-by-step explanation:
This triangle is a 30°-60°-90° triangle. There is a shortcut to find the lengths of the sides of a 30°-60°-90° triangle. The longest side is the hypotenuse. The longest side is double the shortest side or, the shortest side is half the longest side. Here the longest side is 5, so the short leg (shortest side) is 2.5
The other shortcut is that the longer leg is the
short leg×sqroot3
Here, the short leg is 2.5, so the long leg is 2.5×sqroot3
Perimeter is all the sides added together.
5 + 2.5+ 2.5×sqrt3
Do the times first.
5 + 2.5 + 4.3
= 11.8
- Initial velocity=u=0m/s
- Distance=s=150m
- Time=t=10s
- Acceleration=a
Using second equation of kinematics






Using newtons second law


