URGENT WILL GIVE BRAINLIEST

Michelle is painting wooden blocks. he has 11/12 of a quart of paint each block needs 1/6 of a quart to paint. How many blocks c

lara [203]

Answer:5

Step-by-step explanation:

Since Michelle (he ? ) has 11/12 quarts of paint, and need 1/6 per quart to paint, we do 11/12 / 1/6 = 11/2, or 5.5. We cannot paint .5 of a block, so Michelle can only paint 5 quarts.

7 0

3 years ago

Find the values of x and y. The diagram is not to scale.

Aleksandr [31]

Step 1

Find the value of x

we know that

$(x-1)\°=74\°$ -------> by corresponding angles, because the given lines are parallel

Solve for x

$(x-1)\°=74\°\\x=74+1 \\ x=75\°$

Step 2

Find the value of y

we know that

$(x-1)+40+(y-2)=180$

substitute the value of x and solve for y

$(75-1)+40+(y-2)=180$

$74+40-2+y=180$

$112+y=180$

$y=180-112$

$y=68\°$

therefore

the answer is the option B

$x=75\°, y=68\°$

8 0

3 years ago

Read 2 more answers

you are charged $16.05 after tax for a meal. Assume sales tax is 7%, what was the menu price for the meal?

Anton [14]

$1.07x=16.05$

$16.05/1.07=15$

$15=x$

7 0

3 years ago

Read 2 more answers

Explain what the solution to a system of equations is:

WINSTONCH [101]

A solution to a system of equations is a set of values for the variable that satisfy all the equations simultaneously. In order to solve a system of equations, one must find all the sets of values of the variables that constitutes solutions of the system.

3 0

3 years ago

A player of a video game is confronted with a series of four opponents and an 80% probability of defeating each opponent. Assume

mixer [17]

Answer:

(a) 0.4096

(b) 0.64

(c) 0.7942

Step-by-step explanation:

The probability that the player wins is,

$P(W)=0.80$

Then the probability that the player losses is,

$P(L)=1-P(W)=1-0.80=0.20$

The player is playing the video game with 4 different opponents.

It is provided that when the player is defeated by an opponent the game ends.

All the possible ways the player can win is: {L, WL, WWL, WWWL and WWWW)

(a)

The results from all the 4 opponents are independent, i.e. the result of a game played with one opponent is unaffected by the result of the game played with another opponent.

The probability that the player defeats all four opponents in a game is,

P (Player defeats all 4 opponents) = $P(W)\times P(W)\times P(W)\times P(W)=[P(W)]^{4} =(0.80)^{4}=0.4096$

Thus, the probability that the player defeats all four opponents in a game is 0.4096.

(b)

The probability that the player defeats at least two opponents in a game is,

P (Player defeats at least 2) = 1 - P (Player losses the 1st game) - P (Player losses the 2nd game) = $1-P(L)-P(WL)$

$=1-(0.20)-(0.80\times0.20)\\=1-0.20-0.16\\=0.64$

Thus, the probability that the player defeats at least two opponents in a game is 0.64.

(c)

Let X = number of times the player defeats all 4 opponents.

The probability that the player defeats all four opponents in a game is,

P(WWWW) = 0.4096.

Then the random variable $X\sim Bin(n=3, p=0.4096)$

The probability distribution of binomial is:

$P(X=x)={n\choose x}p^{x} (1-p)^{n-x}$

The probability that the player defeats all the 4 opponents at least once is,

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-[{3\choose 0}(0.4096)^{0} (1-0.4096)^{3-0}]\\=1-[1\times1\times (0.5904)^{3}\\=1-0.2058\\=0.7942$

Thus, the probability that the player defeats all the 4 opponents at least once is 0.7942.

3 0

3 years ago