Answer:i tk 180
Step-by-step explanation:
Let the second score = x
⇒ second score = x
<span>the first is 14 points more than the second
</span>⇒ first score = x + 14
<span>the sum of the first two is 6 more than twice the third
</span>⇒ third score = 1/2 (x + x + 14 - 6) = x + 4
<span>The sum of a student's three score is 246
</span>⇒ x + (x + 14) + (x + 4) = 246
<span>
Solve x:
</span>x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76
second score = x = 76
first score = x + 14 = 76 + 14 = 90
Answer: 90
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>
Answer:
Step-by-step explanation:
+ Because of a right triangle, so we can find them- the missing lengths:
+ sin(40)= GH/GF
so GH = GF * sin(40) = 88* sin (40) = 56.565= GH
+ cos( 40) = FH/GF
so FH= GF *cos(40)= 88* cos(40) = 67.412= FH
Have a good day
