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oee [108]
3 years ago
12

Argue whether or not you believe using a sample of students from your school's cafeteria (you recruit the next 100 people to vis

it the cafeteria to participate) may or may not yield biased estimates based on the variable being measured/research question being investigated in each of the following situations.
a. Using the proportion of students with Type O blood to learn about the proportion of U.S. adults with Type O blood
b. Using the proportion of students who eat fast food regularly to learn about the proportion of U.S. college students who eat fast food regularly
Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

Answer: A. <em>Representative, since blood types are probably not different among students at the cafeteria compared to the U.S. population</em>, B. <em>Not representative, since students in the cafeteria may eat most of their meals at the cafeteria instead of eating fast food</em>

Step-by-step explanation:

I Hope that this helps! :)

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NikAS [45]
The answer to this question of yours is B
7 0
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Select the graph that represents two quantities in a proportional relationship.
julia-pushkina [17]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
I don't quite understand this problem: 6+√44/2 (or 6 plus the square root of 44 over 2). I know the answer is 3+√11 (3 plus the
Sonja [21]
Does 2 is included in the square root?
sq.rt (44/2) ? or (sq.rt 44)/2
5 0
3 years ago
Which of the following points are solutions to the system of inequalities shown below?
Ira Lisetskai [31]
Y > 6x + 5
y < -6x + 7
(2,17)
17 > 6(2)+5 ; 17> 17 NO
(8,8)
8>6(8)+5 NO
(-2,18)
18>6(-2)+5
18>-7 YES
18< -6(-2)+7
18< 12+7 YES (-2,18) is an answer
(0,6)
6>6(0)+5
6>5 YES
6<-6(0)+7
6<7 YES (0,6) is an answer
(-2,19)
19>6(-2)+5
19>-7 NO
(2,18)
18>6(2)+5
18>17 YES
18< -6(2)+7
18< -5 NO

3 0
3 years ago
The length of a rectangle is 3 inches more than the width. The area is 10 square inches. Find the dimensions
mr_godi [17]

Answer:

Width = 2

Length = 5

Step-by-step explanation:

let A be the area of the rectangle

   L be the length of the rectangle

   w be the width of the rectangle

<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’

A = L × w

…………………………………………………

A = L × w

⇔ 10 = (w + 3) × w

⇔ 10 = w² + 3w

⇔ w² + 3w - 10 = 0  

<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 =  0 :

Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49

then √Δ = 7

\Longrightarrow w=\frac{-b+\sqrt{\Delta } }{2a} =\frac{-3+7}{2} =2

  or\ w=\frac{-b-\sqrt{\Delta } }{2a} =\frac{-3-7}{2} =-5

-5 is not valid ,because w represents the width

which must be a positive number

Then  w = 2

<u><em>Conclusion</em></u>:

Width = 2

Length = 2 + 3 = 5

6 0
2 years ago
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