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vladimir2022 [97]
3 years ago
15

In quadrilateral WXYZ, ÐW @ ÐY. Which information would help to prove that WXYZ is a parallelogram?

Mathematics
1 answer:
Tanya [424]3 years ago
7 0
Opposite sides are parallel i.e W || Y & X || Z
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At the beginning of 2010, City A had a population of 2,425 and was growing by 27 residents per year. City B had a population of
d1i1m1o1n [39]

Answer: 17 years

Step-by-step explanation:

City A is currently 2,425 people in number and growing at 27 per year.

An expression to find the population in a given year assuming the year is x would be:

= 2,425 + 27 * x

= 2,425 + 27x

Applying the same logic to City B would give an expression of:

= 1,813 + 63x

Equating these together will give the year they will be the same:

2,425 + 27x = 1,813 + 63x

2,425 - 1,813 = 63x - 27x

612 = 36x

x = 612/36

x = 17 years

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3 years ago
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Whats the equivalent fraction to 11/17
MArishka [77]
A simple way to find an equivalent fraction to \frac{11}{17} is to multiply both denominator and numerator. 

So:

11\times2=22\\17\times2=34\\\\ \frac{22}{34}
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3 years ago
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In attempting to solve the system of equations and , John graphed the two equations on his graphing calculator. Because he saw o
asambeis [7]

Answer:

The correct answer is NO.

Step-by-step explanation:

John is graphing two lines with equations say ax + by + c = 0 and dx + ey +f =0 on his graphing calculator.

For John to get a unique solution the coefficients should follow the following condition \frac{a}{d} \neq \frac{b}{e}. So when he plots the lines he get an intersecting pair of lines.

For John to get no solution the coefficients should follow the following condition \frac{a}{d} = \frac{b}{e} \neq  \frac{c}{f}. When we plot in this case we get two parallel lines.

For John to get an infinite many solution the coefficients should follow the following condition \frac{a}{d} = \frac{b}{e} = \frac{c}{f}. And when we plot the lines in this case we get one line superimposed on the other.

Since after graphing, John sees only one line, the lines must have superimposed on one another giving John an infinite number of solutions.

5 0
3 years ago
The monthly sales (in thousands of units) of a seasonal product are approximated by
Elodia [21]
 <span>Don't forget S is measured in thousands of units so you are solving for : 

100 < 74.5 + 43.75Sin(πt/6) 
25.5 < 43.75Sin(πt/6) 
Sin(πt/6) >25.5/43.75 = 0.582857 
ASrcSin(πt/6) > 0.62224 radians 
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This initial value occurs when the sine value is increasing and it will reach its maximum value of 1 when Sin(πt/6) = Sinπ/2, that is when t = 3. 
Consequently, monthly sales exceed 100,000 during the period between t = 1.1884 and 4.8116 
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Note : on the basis of these calculations, January is 0 ≤ t < 1 : February is 1 ≤ t < 2 :....May is 4 ≤ t < 5 
So the period when sales exceed 100,000 occurs between Feb 6 and May 25 and annually thereafter.</span>
3 0
3 years ago
Jorge is making 6 large salads
ladessa [460]

Answer:

what is the rest of your question haha

Step-by-step explanation:

3 0
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