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3 years ago

Help please asap thx

Mathematics

2 answers:

Kay [80]3 years ago

8 0

Answer:

5/2.................

Lelechka [254]3 years ago

7 0

Answer:

2 and a half, but it wants it as a mixed fraction which would be 5/2

Step-by-step explanation:

i hope this helped :)

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The graphed line shown below is y = 5 x minus 10.

harina [27]

Step-by-step explanation:

For 2 lines to form a system with no real solution, the slope of the lines have to be equal and the y-intercept is different.

Hence the answer is y = 5(x + 2).

6 0

3 years ago

Perform the indicated operation & simplify. Express the answer as a complex number. ( 6 − 7 i ) ( − 8 + 3 i ) =___

slega [8]

( 6 − 7 i ) ( − 8 + 3 i )

First FOIL:

( 6 − 7 i ) ( − 8 + 3 i ) = -48 + 18i + 56i -21i^2

Combine like terms

= -48 + 74i -21i^2

Convert i^2 = -1

= -48 + 74i -21(-1)

And simplify

= -48 + 74i + 21

= -27 + 74i

6 0

2 years ago

R^2+6r-40 factor each expression

bearhunter [10]

(r + 10)(r - 4)

To double check:
r * r is r^2

10 * r = 10r; -4 * r = -4r
Combine to get 6r.

-4 * 10 = -40

3 0

3 years ago

Tyron has 27 playlists on his iPod. Each playlist contains 35 songs. How many songs does Tyron have on all of his playlists?

xeze [42]

Answer:

945 songs

Step-by-step explanation:

27*35=945

4 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago