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Nesterboy [21]
3 years ago
10

How do you simplify quadratic equations?

Mathematics
1 answer:
Scrat [10]3 years ago
8 0

Answer:

To solve a quadratic equation by factoring,

Put all terms on one side of the equal sign, leaving zero on the other side.

Factor.

Set each factor equal to zero.

Solve each of these equations.

Check by inserting your answer in the original equation.

Step-by-step explanation:

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The enrollment of a school was 1200. Since then, it has increased at a rate of 35 students per year. Write an equation to repres
Romashka [77]

The general equation to represent the enrollment of the school each year after 2000  = 1200 +35 n    

where n = number of years after 2000.

Step-by-step explanation:

Here, according to the question:

The initial number of students enrolled in the school = 1200 students

The number of students increased each year  = 35 students

Now if the initial year is 2000, then the number of student in the first year

= Initial enrollment  +  ( n  x Number of students increasing each year )

where n : The total number of years after 2000

So, the number of students in first year after 2000 for n = 1 is

1200 + ( 1 x 35)  = 1235

The number of students in second year after 2000 for n = 2  is

1200 + ( 2 x 35)  = 1270

The number of students in third year after 2000 for n = 3 is

1200 + ( 3 x 35)  = 1305

Hence, the general equation to represent the enrollment of the school each year after 2000  = 1200 +35 n    where n = number of years after 2000.

4 0
3 years ago
Read 2 more answers
Solve for x: 1 < x + 3 < 4
Otrada [13]

Answer:

The answer is D

Step-by-step explanation:

1 - 3 < x < 4 - 3 \\  - 2 < x < 1

8 0
3 years ago
7. Find the inverse of f(x) = -2x + 10. Please show work.​
Kipish [7]

Answer- y = - x/2 + 5

Step by step - Replace f (x) with y.

Y = - 2x + 10

Interchange the variables.

x= -2y + 10

Solve for y.

Y= x/2 +5

8 0
3 years ago
Multiple-Choice The average distance
murzikaleks [220]
Alright, so it would be helpful to think about this question in terms of units. You're given a distance (meters) and speed (meters per second). You're asked for time (which is in seconds).

If you do \frac{meters}{meters/second}, your answer will be in seconds. So divide your distance (2.28 x 10^11 meters) by your speed (3.00 x 10^8 meters/second), and you should get your time! 
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saul85 [17]
I think the answer is 596.16
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3 years ago
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