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3 years ago

How do you simplify quadratic equations?

Mathematics

1 answer:

Scrat [10]3 years ago

8 0

Answer:

To solve a quadratic equation by factoring,

Put all terms on one side of the equal sign, leaving zero on the other side.

Factor.

Set each factor equal to zero.

Solve each of these equations.

Check by inserting your answer in the original equation.

Step-by-step explanation:

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The hypotenuse of a right triangle measures 16 cm and one of its legs measures 11 cm.

Zarrin [17]

Answer:

11.6cm

Step-by-step explanation:

a^2+b^2=c^2

11^2+b^2=16^2

121+b^2=256

b^2=135

b=11.6

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3 years ago

Please help me out here I would really appreciate it (will give brainiest if right)

Korvikt [17]

Answer:

265

Step-by-step explanation:

since take the 100 on the left if u put 2 lying down it wont fit, about half of that would fit. So it would be about 265

Mark as brainliest plz

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3 years ago

PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!

garik1379 [7]

Answer:

The correct answer of this question is( larger)

may this answer is helpful for you

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3 years ago

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There are 9 friends playing a card game in which of all of the 52 cards in a standard deck are distributed to the players? How m

horrorfan [7]

Answer:

Step-by-step explanation:

the answer to life and the universe

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3 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2

kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed $a\leq x \leq b$ and in your case $\nexists x\in\mathbb{Z}: a\leq x\leq b$ for $a>b$

In fact, considering a set $S$ we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing$ that satisfy $S = S \cup \varnothing$

This means that, by definition $\sum_{x=a}^b \varnothing = 0$

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

$9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

we have other problems. Actually, this case is really bad.

Note that $\cos^2(\infty)$ has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$ , the cosine function oscillates between $[-1, 1]$ , and therefore it is undefined. Thus, we cannot evaluate

$9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0

3 years ago