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user100 [1]
3 years ago
12

20 POINTS!!!!! I WANT THE RIGHT ANSWER PLEASE

Mathematics
1 answer:
NikAS [45]3 years ago
8 0
One none infinite, hejenhdiekndhxhusjd
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Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.
Masja [62]

Answer:

Step-by-step explanation:

look this solution

5 0
3 years ago
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Lg(5x+10)+2lg3=1+lg(4x+12)<br>need them fast with steps
pashok25 [27]

Answer:

x=6

Step-by-step explanation:

log(5x+10)-log(4x+12)=1-2log(3)

log(5x+10/4x+12)=1-2log(3)

log(5x+10/4x+12)=log(10)+log(3^-2)

log(5x+10/4x+12)=log(10×3^-2)

log(5x+10/4x+12)=log(10×1/9)

log(5x+10/4x+12)=log(10/9)

5x+10/4x+12=10/9

9(5x+10)=(4x+12)10

45x+90=40x+120

5x=30

x=6

if you like my answer. Please mark me as brainliest

5 0
3 years ago
En una ciudad se registró una temperatura de 12°c bajo cero a las 3:00 am si a las 7:00am del mismo dia la temperatura era tres
hjlf

Answer:

24°c

Step-by-step explanation:

Cuando se dice que la temperatura esta "mayor" significaria que esta aumentando y entorno subiendo a ser mas caliente. Siendo este el caso, si la temperatura a las 3:00 estaba a 12c bajo cero entonces a las 7:00 estaria a 24c. Esto es por que un aumento de tres vecesseria un aumento de 36 grados (12*3). 12c grados bajo cero seria un numero negativo y si sumamos estos numeros nos daria 24c grados.

-12 + 36 = 24

7 0
3 years ago
How does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at
Aleks04 [339]
The vehicle traveling 60 mph is going 4 times as fast. the brakes must do an amount of work that's equal to the original kinetic energy. the brakes exert the same amount of force no matter what the case is, so the stopping distance will be four times as long for the car going 60 mph compared to the car going 30 mph.
8 0
3 years ago
*I WILL MARK YOU BRAINLIEST!!!!!*
AlekseyPX
<h2><em> </em><em>Answer:</em></h2>

<em>-</em><em>3</em>

<em>Explanation</em><em>:</em>

<em>Rate </em><em>of </em><em>change </em><em>in </em><em>the </em><em>interval</em>

<em>X=</em><em>0</em><em> </em><em>to </em><em>X=</em><em>3</em><em> </em><em>is </em><em>given </em><em>by,</em>

<em>r =  \frac{f(3) - f(0)}{3 - 0}  \\ here \\ f(3) = 1 \\ f(0) = 10 \\ r =  \frac{1 - 10}{3}  \\  \:  \:  \:  =  \frac{ - 9}{  3}  \\  \:  \:  \:  \:  =  - 3 \\ hope \: it \: helps.....</em>

4 0
4 years ago
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