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Lady bird [3.3K]
3 years ago
10

HELPPSPPS!!! please

Mathematics
2 answers:
Jet001 [13]3 years ago
7 0

Answer:

the answer should be 15 marbles

pshichka [43]3 years ago
3 0
I believe the anwser to be 15 marbles
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there ar 2.54 centimeters in 1 inch. how many cantimeter are in 1 foot? in 1 yard explain you reasoning
VARVARA [1.3K]
There are 30.48 centimeters in a foot
7 0
4 years ago
Suppose that y = k * (x - 1/3) ^ 2 is a parabola in the xy -plane that passes through the point (2/3, 1) :Find k and the length
Dennis_Churaev [7]

Answer:

k = 9

length of chord = 2/3

Step-by-step explanation:

Equation of parabola:   y=k (x-\frac13)^2

<u />

<u>Part 1</u>

If the curve passes through point (\frac23 ,1), this means that when x=\dfrac23, y = 1

Substitute these values into the equation and solve for k:

\implies 1=k \left(\dfrac23-\dfrac13\right)^2

\implies 1=k \left(\dfrac13 \right)^2

Apply the exponent rule \left(\dfrac{a}{b} \right)^c=\dfrac{a^c}{b^c} :

\implies 1=k \left(\dfrac{1^2}{3^2} \right)

\implies 1=\dfrac{1}{9}k

\implies k=9

<u>Part 2</u>

  • The chord of a parabola is a line segment whose endpoints are points on the parabola.  

We are told that one end of the chord is at (\frac23 ,1) and that the chord is horizontal.  Therefore, the y-coordinate of the other end of the chord will also be 1.  Substitute y = 1  into the equation for the parabola and solve for x:

\implies 1=9 \left(x-\dfrac13 \right)^2

\implies \dfrac19 = \left(x-\dfrac13 \right)^2

\implies \sqrt{\dfrac19}  = x-\dfrac13

\implies \pm \dfrac13  = x-\dfrac13

\implies x=\dfrac23, x=0

Therefore, the endpoints of the horizontal chord are: (0, 1) and (2/3, 1)

To calculate the length of the chord, find the difference between the x-coordinates:  

\implies \dfrac23-0=\dfrac23

**Please see attached diagram for drawn graph. Chord is in red**

6 0
2 years ago
What is the best first step in solving the equation 3 + = 5?
Dafna1 [17]

Answer:

5 - 3

Step-by-step explanation:

easy way to find out

5-3= your answer in one step

3 0
3 years ago
how many 5-digit even numbers can be formed with the digits 1,2,3,4,5, and 6 if repetition is allowed?​
Setler79 [48]

Given:

The given digits are 1,2,3,4,5, and 6.

To find:

The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).

Solution:

To form an even number, we need multiples of 2 at ones place.

In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.

We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.

Total number of ways to form a 5 digit even number is:

Total=6\times 6\times 6\times 6\times 3

Total=3888

Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.

6 0
3 years ago
(100 points!)
tatyana61 [14]
Every 10 minutes of reading my book, I read 20 pages each. // part B you read 0.5 minutes per page
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4 years ago
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