Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
secx = 
, cosecx = 
cotx = 
, tanx = 
Consider the left side
secA cosecA - cotA
= 
× 
- 
= 
-
= 
= 
( cancel sinA on numerator/ denominator )
= 
= tanA = right side ⇒ proven
This is never true. In a parallelogram, the diagonals will always bisect each other. Thus, each of these segments would always have to be equal.
Answer is x² + 2x + 5
<u>Step-by-step explanation:</u>
Step 1:
Add the two polynomials
⇒ (2x + 7) + (x² - 2) = 2x + 7 + x² - 2 = x² + 2x + 5
If s=2, then t= 2(2)-3 = 1
T=2(4)-3= 5
T=2(6)-3= 9
T=2(8)-3=13
