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Leto [7]
3 years ago
7

Please i need help. need to turn this in soon Write a inequality that corresponds to this graph.

Mathematics
1 answer:
Sonja [21]3 years ago
7 0

Answer:

x ≥ -4

Step-by-step explanation:

There is a closed circle at -4, which means it is equal to

The line goes to the right, which is greater than

x ≥ -4

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\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

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