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amid [387]
3 years ago
8

Two gongs strike at intervals of 24 and 40minutes respectively. At twist time will they strike together again if they start simu

ltaneously at 12 noon? Hint: 60 minutes = 1 hour
Mathematics
1 answer:
solmaris [256]3 years ago
8 0

Answer:

They will sound together at 2pm

Step-by-step explanation:

Now, the first thing we need to calculate is , in how many minutes will the two gongs strike together.

To be able to do this, we need to calculate the least common multiple of the two numbers 24 and 40

The lowest common multiple between both is 120

This means that the two gongs will sound together at exactly 120 minutes

Now since 1 hour is 60 minutes, this means that 120 minutes will be = 120/60 = 2 hours

Since they both sounded together at 12 noon and the next time they will be sounding is next two hours, their sounding time will thus be 12 noon + 2 hours = 2 pm

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Answer:

See below

Step-by-step explanation:

The first one 'cubes' the denominator AND the numerator:

(-2/5)^3  = -2/5  * -2/5  * -2/5 =  -8/125

The second one 'cubes' only the denominator:

-2/5^3  = -2 / (5 * 5 * 5) =  - 2 / 125

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8 0
3 years ago
Mr. Mole left his burrow and started digging his way down at a constant rate.
Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

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For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

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To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow = -18 - 5(-2.4) = -18+12 = -6.

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