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amid [387]
4 years ago
8

Two gongs strike at intervals of 24 and 40minutes respectively. At twist time will they strike together again if they start simu

ltaneously at 12 noon? Hint: 60 minutes = 1 hour
Mathematics
1 answer:
solmaris [256]4 years ago
8 0

Answer:

They will sound together at 2pm

Step-by-step explanation:

Now, the first thing we need to calculate is , in how many minutes will the two gongs strike together.

To be able to do this, we need to calculate the least common multiple of the two numbers 24 and 40

The lowest common multiple between both is 120

This means that the two gongs will sound together at exactly 120 minutes

Now since 1 hour is 60 minutes, this means that 120 minutes will be = 120/60 = 2 hours

Since they both sounded together at 12 noon and the next time they will be sounding is next two hours, their sounding time will thus be 12 noon + 2 hours = 2 pm

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Which expression is equivalent to (2−√−4)+(1+√−49)? <br> 3−5i <br> 3+5i <br> 8+0i <br> −2+0i
sergij07 [2.7K]

Answer:

3 + 5i.

Step-by-step explanation:

(2−√−4)+(1+√−49)

√−4 = 2i  and

√−49 = 7i.

So   (2−√−4 + (1+√−49

= ( 2 - 2i) + (1 + 7i)

=  3  + -2i + 7i

= 3 + 5i.

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4 years ago
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agasfer [191]

Answer:

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Step-by-step explanation:

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3 years ago
Find the zeros of y = x2 – 6x – 4 by completing the square.
katrin [286]

Answer:

The solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

Step-by-step explanation:

Given the function

y\:=\:x^2\:-\:6x\:-\:4

substitute y = 0 in the equation to determine the zeros

0\:=\:x^2\:-\:6x\:-\:4

Switch sides

x^2-6x-4=0

Add 4 to both sides

x^2-6x-4+4=0+4

Simplify

x^2-6x=4

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2

x^2-6x+\left(-3\right)^2=13

Apply perfect square formula:  (a-b)² = a²-2ab+b²

\left(x-3\right)^2=13

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-3=\sqrt{13}

Add 3 to both sides

x-3+3=\sqrt{13}+3

Simplify

x=\sqrt{13}+3

now solving

x-3=-\sqrt{13}

Add 3 to both sides

x-3+3=-\sqrt{13}+3

Simplify

x=-\sqrt{13}+3

Thus, the solutions to the quadratic equations are:

x=\sqrt{13}+3,\:x=-\sqrt{13}+3

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Step-by-step explanation:

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