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2 years ago

What are the steps for using a compass and straightedge to construct a regular hexagon inscribed in a circle?

1 answer:

N76 [4]2 years ago

3 0

The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:

1. Construct a circle with its center at point H.

2. Construct horizontal line l and point H on line l

3. Label the point of intersection of the circle and line l to the left of point H, point J, and label the point of intersection of the circle and line l to the right of point H, point K.

4. Construct a circle with its center at point J and having radius HJ . Construct a circle with its center at point K having radius HJ

5. Label the point of intersection of circles H and J that lies above line l, point M, and the point of their intersection that lies below line l, point N. Label the point of intersection of circles H and K that lies above line l, point O, and the point of their intersection that lies below line l, point P.

6. Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .

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Name a plane parallel to plane DEF

Verizon [17]

Having two opposite faces plane and parallel a plane-parallel sheet of glass.

Or ?? ⬇️

In geometry, parallel lines are lines in a plane which do not meet; that is, two straight lines in a plane that do not intersect at any point are said to be parallel. Colloquially, curves that do not touch each other or intersect and keep a fixed minimum distance are said to be parallel.

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2 years ago

PLSSS HELP THIS IS HARD ANYONE

Nikolay [14]

Answer:

270 degrees counterclockwise rotation/ the last answer

Step-by-step explanation:

reflection over the y axis wouldn't work bc the shape would still be a horizontal rectangle

dilation would change the size of the shape

and translation wouldn't map it correctly bc it would still be turned the wrong way

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2 years ago

Read 2 more answers

The table shows data from a survey about the amount of time students spend doing homework each week. The students were either in

satela [25.4K]

Answer:

The correct option is: The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

Step-by-step explanation:

We have given a table. According to that table a survey about the amount of time students spend doing homework each week has been conducted. The students were either in college or in high school. Now which of the choices below best describes how to measure the spread of this data.

The correct option is: The college spread is best described by the standard deviation. The high school spread is best described by the IQR.

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3 years ago

Read 2 more answers

1. Solve the equation using the zero-product property. -x(5x – 4) = 0

Oxana [17]

Answer:

x = 0, 4/5

Step-by-step explanation:

The zero-product property states that if the product of a and b is zero, then either a = 0, b = 0, or both terms equal zero

Here our a term is -x and our b term is (5x - 4)
Setting each term equal to zero and solving for x we get
-x = 0 → x = 0
5x - 4 = 0 → 5x = 4 → x = 4/5

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3 years ago

A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The

Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0

3 years ago