Answer:
90 + 29 + x = 180
119 + x = 180
-119 -119
X = 61 degrees
A triangle will always equal 180 degrees.
Given that there is a right triangle it is 90 degrees, also given that 29 degrees is there we add those and add x (the unknown degree) to equal 180 degrees.
Answer:
b) 7.89*10^4
c) 3.15*10^3
Step-by-step explanation:
2-42)
the coefficient in scientific notation (the number that is not 10^x) has to be greater or equal to 1 and less than 10. so c and b are incorrect.
b) 0.789*10^5
c) 31.5*10^2
b) 0.789*10^5
in order to make 0.789 greater than 1, I would just multiply it by 10. shown below
=0.789*10*10*10*10*10
=7.89*10*10*10*10
=7.89*10^4
c) 31.5*10^2
same concept but this time divide by 10 to make 3.15 which will add another *10 to the exponent
=31.5*10*10
=3.15*10*10*10
=3.15*10^3
well, the sequence goes, 1100, to 1135, to 1170.... notice, is simply adding 35 to get the next term, so the common difference is 35, and the first term is 1100 of course.
![\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=1100\\ d=35\\ a_n=3725 \end{cases} \\\\\\ 3725=1100+(n-1)35\implies 3725=1100+35n-35 \\\\\\ 3725=1065+35n\implies 2660=35n\implies \cfrac{2660}{35}=n\implies 76=n](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20an%20arithmetic%20sequence%7D%0A%5C%5C%5C%5C%0Aa_n%3Da_1%2B%28n-1%29d%5Cqquad%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ad%3D%5Ctextit%7Bcommon%20difference%7D%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa_1%3D1100%5C%5C%0Ad%3D35%5C%5C%0Aa_n%3D3725%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A3725%3D1100%2B%28n-1%2935%5Cimplies%203725%3D1100%2B35n-35%0A%5C%5C%5C%5C%5C%5C%0A3725%3D1065%2B35n%5Cimplies%202660%3D35n%5Cimplies%20%5Ccfrac%7B2660%7D%7B35%7D%3Dn%5Cimplies%2076%3Dn)
The answer to this question is 12
The answer for this question would be C) Guerilla warfare or the third option.
