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2 years ago

Is algebra.

Mathematics

1 answer:

aksik [14]2 years ago

4 0

Answer:

In the first one answer is r²

In second one answer is 3

Step-by-step explanation:

Yes it is Algebra with different powers

In first one (6r4+4r) +(__- 2r4 + 3r) = 4r4 + r2 + 7r

Like terms are added:

6r^4- 2r^4 + 4r + 3r +____ = 4r^4 + r2+ 7r

4r^4+7r +___ = 4r^4 + r^2 + 7r

Therefore ___ = r^2

In second one:

(__ -8x - x^2)-(4x^2 -7 +6x) = -5x^2 +14x +10

Open the brackets

__ -8x - x^2-4x^2 +7 -6x = -5x^2 +14x +10

Add like terms

__ -14x -5x^2 + 7= -5x^2 +14x +10

Therefore

___ + 7 = 10

___ = 10 -7 = 3

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Ede4ka [16]

Answer:

The object hits the ground in 5 seconds.

Step-by-step explanation:

Given : An object is launched at 9.8 meters per second from 73.5 meter tall platform. The objects height s (in meters) after t seconds I’d given by the equation $s(t)= -4.9t^2-9.8t+73.5$ .

To find : Use the factoring to determine when the object hits the ground ?

Solution :

When the object hits the ground the distance is zero.

i.e. s(t)=0

So, $-4.9t^2-9.8t+73.5=0$

Applying quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=-4.9, b=-9.8 and c=73.5

$t=\frac{-(-9.8)\pm\sqrt{(-9.8)^2-4(-4.9)(73.5)}}{2(-4.9)}$

$t=\frac{9.8\pm\sqrt{1536.64}}{-9.8}$

$t=\frac{9.8\pm 39.2}{-9.8}$

$t=1\pm 4$

$t=1+4,1-4$

$t=5,-3$

Reject t=-3

Therefore, the object hits the ground in 5 seconds.

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Step-by-step explanation:

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