Answer:
To complete the problem statement it is needed:
1.- the volume and weight capacity of the truck, because these will become the constraints.
2.- In order to formulate the objective function we need to have an expression like this:
" How many of each type of crated cargo should the company shipped to maximize profit".
Solution:
z(max) = 175 $
x = 1
y = 1
Assuming a weight constraint 700 pounds and
volume constraint 150 ft³ we can formulate an integer linear programming problem ( I don´t know if with that constraints such formulation will be feasible, but that is another thing)
Step-by-step explanation:
crated cargo A (x) volume 50 ft³ weigh 200 pounds
crated cargo B (y) volume 10 ft³ weigh 360 pounds
Constraints: Volume 150 ft³
50*x + 10*y ≤ 150
Weight contraint: 700 pounds
200*x + 360*y ≤ 700
general constraints
x ≥ 0 y ≥ 0 both integers
Final formulation:
Objective function:
z = 75*x + 100*y to maximize
Subject to:
50*x + 10*y ≤ 150
200*x + 360*y ≤ 700
x ≥ 0 y ≥ 0 integers
After 4 iterations with the on-line solver the solution
z(max) = 175 $
x = 1
y = 1
Answer:
88
Step-by-step explanation:
33 ÷ 3/8
------------------
3/8 = 0.375
------------------------
33 ÷ 0.375 = 88
Answer:
A
Step-by-step explanation:
Answer: She had 27.2% correct.
Step-by-step explanation: To find the percent, we can divide the part and whole then multiply the quotient by 100. After that we'll need to convert the percent to a decimal. In mathematical terms, the formula will be,
40% will be the part and 68% will be the whole.
<u><em>Step 1.</em></u>
Convert 40 into a decimal by dividing it by 100.
40 ÷ 100 = 0.4
<u><em>Step 2.</em></u>
Multiply 0.4 by 68.
0.4 × 68 = 27.2
Hence, she had 27.2% correct.
You can switch the addition and subtraction signs to get q-(+5) =? So you want to find what 5 can be subtracted from to get 3, which is 8. 8+(-5) =3
