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Kisachek [45]
3 years ago
5

..................................

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Type in the equation of the graphing calculator and press graph

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The vertices of figure BCDE have coordinates B(4, 4) , C(−4, 4), D(−4, −4) , and E(4, −4) . The vertices of figure B'C'D'E' have
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Read 2 more answers
What is 5 1/2 of 60%
EleoNora [17]
You mean 60%of 5 1/2? that makes more sense...


i would do it like this:

\frac{60}{100}* 5\frac{1}{2}

(60% is the same as \frac{60}{100}

5\frac{1}{2}=\frac{11}{2}

(so that there is no confusion, i've put it into an improper fraction

now we can multiply:
\frac{60}{100}* \frac{11}{2}=

\frac{6}{10}* \frac{11}{2}=

\frac{3}{5}* \frac{1}{2}=



\frac{3*11}{10}=

\frac{33}{10}=

which is 3.3.

so 60% of 5 and a half is 3.3.


6 0
3 years ago
CALCULUS EXPERT WANTED. Can someone solve this or at least try to explain to me the fundamental theorem of calculus (FTC).
Amanda [17]

a. By the FTC,

\displaystyle\frac{\mathrm d}{\mathrm dx}\int_1^{\cos x}(t+\sqrt t)\,\mathrm dt=(\cos x+\sqrt{\cos x})\dfrac{\mathrm d}{\mathrm dx}\cos x=-\sin x(\cos x+\sqrt{\cos x})

b. We can either evaluate the integral directly, or take the integral of the previous result. With the first method, we get

\displaystyle\int_1^{\cos x}(t+\sqrt t)\,\mathrm dt=\dfrac{t^2}2+\dfrac{2t^{3/2}}3\bigg|_{t=1}^{t=\cos x}=\left(\dfrac{\cos^2x}2+\dfrac{2(\cos x)^{3/2}}3\right)-\left(\dfrac12+\dfrac23\right)

=\dfrac{\cos^2x}2+\dfrac{2\sqrt{\cos^3x}}3-\dfrac76

c. The derivative of the previous result is

\dfrac{2\cos x(-\sin x)}2+\dfrac{2\cdot\frac32(\cos x)^{1/2}(-\sin x)}3=-\sin x\cos x-\sin x\sqrt{\cos x}

which is the same as the answer given in part (a), so ...

d. ... yes

4 0
3 years ago
The product of two consecutive positive integers is 11 more than their sum. Find the integers.
Sergio039 [100]
4 and 5. 4+5 =9 and 4x5 =20 which is 11 more than 9
5 0
2 years ago
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