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sergiy2304 [10]
3 years ago
9

What’s the length of the hypotenuse in inches?

Mathematics
2 answers:
natta225 [31]3 years ago
5 0

Answer:

The hypotenuse is 25 inches.

Step-by-step explanation:

This is a right triangle, so the Pythagorean Theorem applies.

I will assume you know about the Pythagorean Theorem, therefore I will not define it.

Here, I am solving for the hypotenuse.

a^2+b^2=c^2

24^2+7^2=c^2

576+49=c^2

625 = c^2

25=c

ch4aika [34]3 years ago
4 0

Answer:

25

Step-by-step explanation:

To find the hypotenuse, you need to use a^2+b^2=c^2

Plugging the numbers in, the equation is

24^2+7^2=c^2

From here, you can just solve the equation, simplifying it equals

576+49=c^2

Add the two values

625=c^2

from here, you would square both sides to get c standing alone. This results in the equation finishing with the answer:

25=c

or flipping it around to make sence

c=25

Hope this helps! Have a good rest of your day!!!

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Use the empirical rule to solve the problem. The annual precipitation for one city is normally distributed with a mean of 288 in
nadezda [96]

Answer:

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:

X \sim N(288,3.7)  

Where \mu=288 and \sigma=3.7

The confidence level is 95.44 and the signficance is 1-0.9544=0.0456 and the value of \alpha/2 =0.0228. And the critical value for this case is z = \pm 1.99

Using this condition we can find the limits

z=-1.99

z=1.99

And if we solve for a we got

a=288 -1.99*3.7=214.4

a=288 +1.99*3.7=295.4

And the limits for this case are: (214.4; 295.4)

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Answer:

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Step-by-step explanation:

the denominator is the number that is down or under the fraction line

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Answer:

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