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2 years ago

VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.

Mathematics

1 answer:

melomori [17]2 years ago

5 0

Answer:

It is D Because I'm soo Smart And the Question is easy

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Use the image below to answer the following question. What relationship do the ratios of sin x° and cos y° share?

Drupady [299]

Answer:

Step-by-step explanation:

$y \times {4 \div 14 \frac{10}{4 |25 \\ | } }^{2}$

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2 years ago

There are two urns, each of them containing two blue balls and two red balls. We randomly draw two balls from the first urn and

mafiozo [28]

Answer: 50/50

Step-by-step explanation:

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3 years ago

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adell [148]

What is the question??

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3 years ago

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What is the greatest common factor of 54x^3, 18x, 36x^2

Alex73 [517]

It’s 18x because 36 and 54 are both divisible by 18, and 18 can be divisible by 18 (making 1), resulting in 18 being the most common number between the numbers, whereas the ‘x’ is common between all 3 numbers and since the least amount of x is 1, the answer is just x without an exponent

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3 years ago

Which expression is equivalent to...? Screenshots attached. Please help! Thank you.

Studentka2010 [4]

Answer:

$4x^{3} y^{2} (\sqrt[3]{4 x y})$

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

$\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }$

Then we'll extract the 4 from the cubic root. We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

$\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }$

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

$4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }$

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

$4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}$

The answer is then:

$4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})$

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3 years ago